Forum Discussion
8 years ago
Here is some math(Sorry for my english!!!):
Maximize earning cash (or xp without farming)
K1=constant (cash or xp earned)
T=Total Item considerate
M= Average multiplier per item (i.e. 2% => 0.02)
X=Item with multiplier
So you can earn:
$=K*(T-X)(1+M*X)=K(T+T*M*X-X-MX^2)
If the derivate is equal to 0 we find the maximum.
K(TM-1-2*M*X) =0
X = T/2-1/(2M)
If you use all 10000 item and you have an average multiplayer of 2% X=4975 and your multiplier is 4975*2=9950%
Maximize xp (With farm):
K2=K1*(xp earned with farming)/ ($ used)
C=Collider coefficient, it can be 1 or 5.
XP=K2(1+M*C*X)(T-X)(1+MX)
After derivate and rearrangement, we have:
(3*C*M^2)X^2- 2*M(M*C*T – C – M) - M*T(C+1) – 1=0
So you maximize xp if item with multiplier are 66-67% of the total.
If you want to use 10000 item and you think that your average multiplier is 1% the final multiplier is 6600-6700%
Maximize earning cash (or xp without farming)
K1=constant (cash or xp earned)
T=Total Item considerate
M= Average multiplier per item (i.e. 2% => 0.02)
X=Item with multiplier
So you can earn:
$=K*(T-X)(1+M*X)=K(T+T*M*X-X-MX^2)
If the derivate is equal to 0 we find the maximum.
K(TM-1-2*M*X) =0
X = T/2-1/(2M)
If you use all 10000 item and you have an average multiplayer of 2% X=4975 and your multiplier is 4975*2=9950%
Maximize xp (With farm):
K2=K1*(xp earned with farming)/ ($ used)
C=Collider coefficient, it can be 1 or 5.
XP=K2(1+M*C*X)(T-X)(1+MX)
After derivate and rearrangement, we have:
(3*C*M^2)X^2- 2*M(M*C*T – C – M) - M*T(C+1) – 1=0
So you maximize xp if item with multiplier are 66-67% of the total.
If you want to use 10000 item and you think that your average multiplier is 1% the final multiplier is 6600-6700%
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