Possible Solo P3 HAAT Team

"Lugo;c-1101984" wrote:

"Woodroward;c-1101982" wrote:

"Jedidude5060;c-1101945" wrote:
How are these toons modded?

I would suggest crit damage sets with triangle on most if not all of them (Teebo may want all potency mods).

Primary/Secondary stats:
Potency and crit chance on Teebo. Potency and health on Chewie (for tm removal and making his heal as effective as possible). Speed and Crit Chance on Ewok Elder. Speed and offense on Nute Gunray. If you run Chirpa instead of Chewie, I would do Speed and crit chance on him too.


At least that's what would seem to be most effective to me.

Agreed

I forgot to mention R2. He will need speed and crit chance too.

I would say that Ewok Elder and R2 should have the fastest speed mods since Ewok Elder's speed directly and consistently affects the other Ewok's speeds, and to make sure that R2 can keep up with teebo enough to keep him in stealth. His stealth is a 4 turn cooldown to Teebo's 5 turn cooldown, so he's got that going for him, but he won't get anywhere near the tm gain that Teebo will be getting.

Here's a formula for calculating how fast your R2 needs to be to keep up with your Teebo assuming Ewok Elder goes five times in the same time that Teebo does and procs his tm gain half the time:

2700 / (1750 / TS) = RS
TS = Teebo's speed
RS = R2's speed.

By this formula and assumptions, a Teebo with a single speed arrow would require a 229 speed R2 to keep up with him.

Ewok Elder will give more tm to teebo than R2, so as your Ewok Elder goes more and more. you'll need a faster and faster R2 to keep up with the same speed Teebo, so when in doubt, err by making R2 too fast.





Theory behind the formula:
5 turns for Teebo = 5000
4 turns for R2 = 4000
Teebo should be stealthed and critting every turn, so only need to fill up half of each turn. 5000/2 = 2500
R2 should be stealthed and critting for 2 of his 4 turns so we can subtract 500 for each of those turns 4000 - 2(500) = 3000

If Ewok Elder goes 1:1 with Teebo he could potentially give him 5 * 250 = 1250 turn meter in the time it takes for his cd to reset. At a 60% proc rate that's 1250 * .6 = 750 So we subtract that from how much tm he really needs to fill to reach his cooldown again 2500 - 750 = 1750

Likewise R2 could gain up to 100 * 5 = 500 tm. 60% proc rate 500 * .6 = 300. 3000 - 300 = 2700

So by determining how many increments it will take for Teebo's cooldown to recharge with 1750 / Teebo's speed and then dividing 2700 by the result we can determine what speed R2 needs to be at to have his cooldown refresh right before Teebo drops out of stealth.