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mathematics654
5 years agoSeasoned Ace
128 isn't divisible by 5, but it is divisible by 4, which make 32 squads of 4, if it was 5 then some players won't have a full squad, the next divisible number is 8, which is a way too large squad
5 years ago
@mathematics654Haha, very good and living up to your name. Good point but I dont think its that critical for a completely perfect division of equal squads. As soon as one player locks a squad, the division problem changes randomly anyways. So let there possibly be one squad that is a little undermanned.
With squads of 5 players per squad, and assuming no one locks a squad, your actual chances of being in the 3 man left over squad are about 2 percent. Or one chance in 50. Worth the risk to have 5 men per squad.
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