Jolee Bindo - Kenobi synergy
I along with many others are very excited about the (working) Bastilla leveling the playing field against the sith. We've all had to deal with the sith being op against the jedi for so long. I was ver...
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You are right about hoda, I was wrong about that. However as it stands now without jolee, a gk lead stacked with healers can potentially launch 5 swarms in a row. I not sure if you're actually reading my replies, but I've stated there are restrictions on the effectiveness of this strategy.
1.It can be countered by several abilities employed by the sith
2. It requires you stack the team with healers who have less damage potential, not to mention the damage penalty applies to extra attackers.
3. If Traya is the lead it is impossible to launch this strategy because she removes 35% health from anyone attacking out of turn, and units need to be at 100% health to participate in the swarm attack.
4. Etc, etc,etc....
Like I said even without jolee five swarms in a row is already possible and nobody calls that op, mainly because of the limiting factors I stated above. So that has been around this entire time and nobody has ever called the jedi op. So despite your reasoning and yoda quotes, saying jolee having this synergy is OP is just plain wrong.
1.It can be countered by several abilities employed by the sith
2. It requires you stack the team with healers who have less damage potential, not to mention the damage penalty applies to extra attackers.
3. If Traya is the lead it is impossible to launch this strategy because she removes 35% health from anyone attacking out of turn, and units need to be at 100% health to participate in the swarm attack.
4. Etc, etc,etc....
Like I said even without jolee five swarms in a row is already possible and nobody calls that op, mainly because of the limiting factors I stated above. So that has been around this entire time and nobody has ever called the jedi op. So despite your reasoning and yoda quotes, saying jolee having this synergy is OP is just plain wrong.
