11 straight phasma extra attacks.
That's a 1 in 10^9 ish chance. Add in mine never proc ing and we have a 1 in 10 19ish chance of happening. I should buy a lotto ticket.
Forum Discussion
"Eaywen;5952" wrote:
That's a 1 in 10^9 ish chance. Add in mine never proc ing and we have a 1 in 10 19ish chance of happening. I should buy a lotto ticket.
Well, that is the "in" thing to do nowadays.- Nothing like 1 in 10^9 chance, it's actually 1.76%, still long odds but almost a 2% chance. If only the Powerball lottery had such good odds.
Based on a 16% proc rate of an assist times 11 in a row, you get the following formula:
(16/100)11 =1.76% "Jabberwocky;50009" wrote:
Nothing like 1 in 10^9 chance, it's actually 1.76%, still long odds but almost a 2% chance. If only the Powerball lottery had such good odds.
Based on a 16% proc rate of an assist times 11 in a row, you get the following formula:
(16/100)11 =1.76%
Actually it's much lower. It would be (0.16)^11
Which is about 1 in 568,000,000.
So yes, less likely than winning the powerball lottery.- Yeah. I did a message one of the CG guys about this yesterday happening to me as well. Exactly 11 straight procs before it failed to. Insane odds and figure Phasma has to be bugged
- Perhaps the roll doesn't go down exactly as written.
"Jabberwocky;50009" wrote:
Nothing like 1 in 10^9 chance, it's actually 1.76%, still long odds but almost a 2% chance. If only the Powerball lottery had such good odds.
Based on a 16% proc rate of an assist times 11 in a row, you get the following formula:
(16/100)11 =1.76%"Baal;50141" wrote:
16% is 16% and 11 is well within common expectations.
...Somebodies weren't paying attention in 9th grade math class. Or maybe you are just American?
It should be (16/100)^11. That's 16% to the power of 11, not times 11."Rheen;50018" wrote:
Actually it's much lower. It would be (0.16)^11
Which is about 1 in 568,000,000.
To be precise 568,434,188.608 in one chance. You probably would have won the lottery."DarthHernia;50238" wrote:
"Jabberwocky;50009" wrote:
Nothing like 1 in 10^9 chance, it's actually 1.76%, still long odds but almost a 2% chance. If only the Powerball lottery had such good odds.
Based on a 16% proc rate of an assist times 11 in a row, you get the following formula:
(16/100)11 =1.76%"Baal;50141" wrote:
16% is 16% and 11 is well within common expectations.
...Somebodies weren't paying attention in 9th grade math class. Or maybe you are just American?
It should be (16/100)^11. That's 16% to the power of 11, not times 11."Rheen;50018" wrote:
Actually it's much lower. It would be (0.16)^11
Which is about 1 in 568,000,000.
To be precise 568,434,188.608 in one chance. You probably would have won the lottery.
He's right. It's 0.16 X 0.16 X 0.16 etc"Sejalx;50602" wrote:
Nerds
Nerd = financially well off :) Modern economy is all about STEM!- @Cyclonus is right.
Probably of getting 11 assists in a row after having already received 10 assists: 1/6. (People don't believe this, though, feeling the other result is "overdue" after a long string. It's called the Gambler's Fallacy: https://en.wikipedia.org/wiki/Gambler's_fallacy).
Probably of getting 11 assists from the start of a match: a number so low that while possible, it suggests a possible bug. - Mathematical Proof: Divide pi by the golden ratio and then add the Fibonacci sequence to every other prime digit right of the decimal point. Assign each digit to a different person on the server and have them flip a coin. Take those values and use kth nearest neighbor analysis each time, where k is RNGed. Run a regression analysis on the results from each server, and take the p-value divided by the R-squared. That's the answer.
