Yeah more like TFP has a 90% chance to gain foresight

"MarkMcC1993;901834" wrote:
From what I can gather the odds are as follows on the assumption that each individual attempt is programmed as a unique dice roll with the 35/65 odds. This gives him the following total chances:

1 debuffed enemy = 35.00%
2 debuffed enemies = 57.75%
3 debuffed enemies = 72.54%
4 debuffed enemies = 81.15%
5 debuffed enemies = 87.40%
Tank:
6 debuffed enemies = 91.46%
7 debuffed enemies = 94.10%

Interestingly it would never reach 100% chance no matter how many debuffed enemies existed If you want the mathematical formula it would be as follows:

0.35 + 0.35 Σ 0.65^(n-1) ..... where n = number of debuffed enemies

After 3 debuffed enemies, your results seem to be off by 1% from what I'm getting.

Also, what is the summation over in your formula? 0.65^(n-1) is a constant. If you meant to say SUM i=1, N, then you would have 0.65^(1-1)=1 in your summation, and doing the expansion you would have p+p+SUM (other positive values). You see that in the case of p=0.5, this value exceeds 1. Also, if you meant to sum over i=0, N, you would wind up with q^(0-1) = 1/q, and in the case of q=0, this also presents a problem.

So I wad just a little confused and wondering if you could provide clarification on your formula.